Ex1-7

How-to-retrieve-data-from-two-or-more-tables.sql

@@ -1,19 +1,85 @@
+-- Exercise 1 --
+SELECT 
+	category_name, 
+    product_name, 
+    list_price
+FROM products p JOIN categories c 
+	ON p.category_id = c.category_id
+ORDER BY category_name, product_name;
 
+-- Exercise 2 --
+SELECT
+	first_name, 
+    last_name, 
+    line1, 
+    city,
+    state, 
+    zip_code
+FROM customers c JOIN addresses a 
+	ON c.customer_id = a.customer_id
+WHERE email_address LIKE 'allan.sherwood@yahoo.com';
 
+-- Exercise 3 --
+SELECT
+	first_name, 
+    last_name, 
+    line1, 
+    city,
+    state, 
+    zip_code
+FROM addresses a JOIN customers c 
+	ON c.customer_id = a.customer_id AND c.shipping_address_id = address_id;
 
+-- Exercise 4 --
+SELECT 
+	last_name AS 'Last Name',
+	first_name AS 'Fist Name',
+	order_date AS 'Order Date',
+	product_name AS 'Product Name',
+	item_price AS 'Item Price', 
+	discount_amount AS 'Discount Amount',
+	quantity AS 'Quantity'
+FROM customers c 
+	JOIN orders o 
+		ON c.customer_id = o.customer_id 
+    JOIN order_items oi 
+		ON  oi.order_id =  o.order_id
+	JOIN products p
+		ON p.product_id = oi.product_id
+ORDER BY last_name, order_date, product_name;
 
 
+-- Exercise 5 --
+SELECT 
+    p.list_price, 
+    p.product_name
+FROM products p INNER JOIN products p2
+	ON p.list_price = p2.list_price
+WHERE p.product_id != p2.product_id
+ORDER BY product_name;
 
+-- Exercise 6 --
+SELECT
+	category_name,
+    product_id
+FROM categories c LEFT OUTER JOIN products p 
+	ON c.category_id = p.category_id
+WHERE p.product_id IS NULL;
 
+-- Exercise 7 --
+SELECT
+	'SHIPPED' AS ship_status,
+    order_id,
+    order_date
+FROM orders o
+WHERE ship_date IS NOT NULL
 
-
-
-
-
+		UNION
+    
+SELECT 
+	'NOT SHIPPED' AS ship_status,
+	order_id,
+    order_date
+FROM orders o
+WHERE ship_date IS NULL
+ORDER BY order_date;