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How-to-code-subqueries.sql

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+-- Exercise 1
+SELECT DISTINCT category_name
+FROM categories c JOIN products p
+ ON c.category_id = p.category_id
+WHERE (
+SELECT DISTINCT category_name
+FROM categories c JOIN products p
+ ON c.category_id = p.category_id)
+ORDER BY category_name
+-- Exercise 2
+SELECT product_name,list_price
+FROM products
+WHERE (
+    SELECT product_name,list_price
+	FROM products)
+ORDER BY list_price DESC;
+-- Exercise 3
+SELECT category_name 
+FROM categories
+WHERE (
+    SELECT product_id
+		FROM products)
+WHERE product_id NOT EXISTS
+ORDER BY category_id DESC;
+-- Exercise 4
+SELECT email_address, order_id,sum(item_price) AS order_total
+FROM administrators a JOIN orders o
+  ON a.admin_id = o.admin_id
+ORDER BY email_address ASC;
+
+-- Exercise 4 part 2
+__
+-- Exercise 5
+SELECT product_name, discount_percent
+FROM products
+ORDER BY discount_percent DESC;
+-- Exercise 6
+SELECT email_address, order_id, order_date
+FROM administrators a JOIN orders o
+on a.admin_id = o.order_id;

How-to-code-summary-queries.sql

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+-- Exercise 1
+SELECT COUNT(order_id) AS order_count, SUM(tax_amount) AS tax_total
+FROM orders;
+
+-- Exercise 2
+SELECT category_name, COUNT(product_name) AS product_count, sum(list_price)
+FROM categories c JOIN products p
+	ON c.category_id = p.category_id.
+ORDER BY category_name ASC;
+
+-- Exercise 3
+SELECT email_adress,SUM(item_price*quantity) AS item_price_total, SUM(discount_amount*quantity) AS discount_amount
+FROM administrators c JOIN order_items l
+	ON c.admin_id = l.admin_id
+ORDER BY item_price DESC; 
+
+-- Exercise 4
+SELECT email_adress, COUNT(order_id) AS order_count, SUM((ship_amount-tax_amount)*quantity) AS order_total
+FROM administrators c JOIN orders o 
+	ON c.admin_id_id = o.admin_id
+WHERE admin_id > 1
+ORDER BY SUM(list_price) DESC;
+
+-- Exercise 5
+SELECT email_adress, COUNT(order_id) AS order_count, SUM((ship_amount-tax_amount)*quantity) AS order_total
+FROM administrators c JOIN orders o 
+	ON c.admin_id_id = o.admin_id
+WHERE order_id >= 400
+ORDER BY SUM(list_price) DESC;
+
+-- Exercise 6
+
+
+-- Exercise 7
+SELECT email_adress, sum(product_id) AS number_of_products
+FROM administrators a JOIN products p
+ON a.admin_id = p.admin_id
+ORDER BY admin_id ASC;

How-to-retrieve-data-from-a-single-table.sql

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+-- Exercise 1
+
+SELECT product_code,product_name,list_price,discount_percent
+FROM products
+ORDER BY list_price DESC;
+
+-- Exercise 2
+SELECT CONCAT(last_name+', '+first_name) AS full_name
+FROM customers;
+
+-- Exercise 3
+SELECT product_name,list_price,date_added
+FROM products
+WHERE list_price > 500 AND list_price < 1200
+ORDER BY date_added DESC;
+
+-- Exercise 4
+SELECT product_name,list_price,discount_percent,(list_price*discount_percent/100)AS discount_amount,(list_price -(list_price*discount_percent/100))AS discount_price
+FROM products
+ORDER BY list_price DESC LIMIT 5;
+
+-- Exercise 5
+SELECT item_id,item_price,discount_amount,quantity,(item_price*quantity)AS price_total,(discount_amount*quantity)AS discount_total,(item_price*quantity)-(discount_amount*quantity)AS item_total
+FROM order_items
+ORDER BY item_price DESC LIMIT 5;
+
+-- Exercise 6
+SELECT order_id,order_date,ship_date
+FROM orders
+WHERE ship_date IS null;
+
+-- Exercise 7
+SELECT NOW()=today_unformatted,
+	  (DD-Mon-YYYY)=today_formatted;
+
+-- Exercise 8
+SELECT list_price as price,
+       discount_percent as tax_rate,
+       (list_price*discount_percent/100) AS tax_amount,
+       list_price*(list_price*discount_percent/100) AS total
+FROM products;       

How-to-retrieve-data-from-two-or-more-tables.sql

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+-- Exercise 1
+SELECT category_name, product_name, list_price
+FROM categories c JOIN products p
+     ON c.category_id = p.category_id
+ORDER BY category_name,product_name ASC;   
+
+-- Exercise 2
+SELECT first_name, last_name, line1, city, state, zip_code  
+FROM customers c JOIN addresses a
+   ON c.customer_id = a.customer_id
+WHERE state='NJ'	 
+ORDER BY customers ASC;
+
+-- Exercise 3
+SELECT first_name, last_name, line1, city, state, zip_code  
+FROM customers c JOIN addresses a
+   ON c.customer_id = a.customer_id	 
+ORDER BY first_name ASC;
+
+-- Exercise 4
+SELECT last_name, first_name, order_date, product_name, item_price, discount_amount, quantity
+   FROM customers c JOIN products p AND orders o JOIN order_items i 
+        ON c.customer_id = p.category_id AND o.order_id = i.order_id
+ORDER BY last_name, order_date, product_name ASC; 
+
+-- Exercise 5
+SELECT product_name, list_price
+FROM products(
+    SELECT product_name, list_price
+	FROM products)
+ORDER BY product_name ASC; 
+
+-- Exercise 6
+	SELECT product_name, list_price
+FROM products(
+    SELECT product_name, list_price
+	FROM products)
+WHERE product_name IS null    
+ORDER BY product_name ASC;
+
+-- Exercise 7
+SELECT ship_date, order_id, order_date
+   FROM orders;