made exercises

How-to-code-summary-queries.sql

@@ -1,16 +1,14 @@
     -- Exercise 1
 
-    SELECT 
-    COUNT(order_id),
-    SUM(tax_amount)
+    SELECT COUNT(order_id),
+    	SUM(tax_amount)
     FROM orders;
 
     -- Exercise 2
 
-    SELECT 
-    category_name,
-    COUNT(product_id) AS count,
-    MAX(list_price) AS max_price
+    SELECT category_name,
+    	COUNT(product_id) AS count,
+        MAX(list_price) AS max_price
     FROM categories c JOIN products p
     ON c.category_id = p.category_id
     GROUP BY category_name
@@ -18,41 +16,38 @@
 
     -- Exercise 3
 
-    SELECT 
-    c.email_address,
-    SUM(item_price) * quantity,
-    SUM(discount_amount) * quantity
+    SELECT c.email_address,
+    	SUM(item_price) * quantity,
+        SUM(discount_amount) * quantity
     FROM orders o JOIN order_items i 
-    ON o.order_id = i.order_id
-    JOIN customers c 
-    ON o.customer_id = c.customer_id
+    		ON o.order_id = i.order_id
+        JOIN customers c 
+        ON o.customer_id = c.customer_id
     GROUP BY c.customer_id
     ORDER BY item_price DESC;
 
     -- Exercise 4
 
-    SELECT 
-    c.email_address,
-    COUNT(i.order_id),
-    SUM(item_price - discount_amount) * quantity AS 'total_amount'
+    SELECT c.email_address,
+    	COUNT(i.order_id),
+        SUM(item_price - discount_amount) * quantity AS 'total_amount'
     FROM orders o JOIN order_items i
-    ON i.order_id = o.order_id
-    JOIN customers c
-    ON o.customer_id = c.customer_id
+    		ON i.order_id = o.order_id
+    	JOIN customers c
+    		ON o.customer_id = c.customer_id
     GROUP BY email_address
     HAVING COUNT(i.order_id) > 1
     ORDER BY SUM(item_price - discount_amount) * COUNT(i.order_id) DESC;
 
     -- Exercise 5
 
-    SELECT 
-    c.email_address,
-    COUNT(i.order_id),
-    SUM(item_price - discount_amount) * quantity AS 'total_amount'
+    SELECT c.email_address,
+    	COUNT(i.order_id),
+        SUM(item_price - discount_amount) * quantity AS 'total_amount'
     FROM orders o JOIN order_items i
-    ON i.order_id = o.order_id
-    JOIN customers c
-    ON o.customer_id = c.customer_id
+    		ON i.order_id = o.order_id
+    	JOIN customers c
+    		ON o.customer_id = c.customer_id
     WHERE i.item_price > 400
     GROUP BY email_address
     HAVING COUNT(i.order_id) > 1
@@ -60,22 +55,20 @@
 
     -- Exercise 6
 
-    SELECT 
-    product_name,
-    SUM(item_price - discount_amount) * quantity AS 'total_amount'
+    SELECT product_name,
+        SUM(item_price - discount_amount) * quantity AS 'total_amount'
     FROM products p JOIN order_items i
-    ON p.product_id = i.product_id
+    	ON p.product_id = i.product_id
     GROUP BY product_name WITH ROLLUP;
 
     -- Exercise 7
 
-    SELECT 
-    email_address,
-    COUNT(product_id) AS 'distinct_products'
+    SELECT email_address,
+        COUNT(product_id) AS 'distinct_products'
     FROM customers c JOIN orders o
-    ON c.customer_id = o.customer_id
+    	ON c.customer_id = o.customer_id
     JOIN order_items i 
-    ON o.order_id = i.order_id
+    	ON o.order_id = i.order_id
     GROUP BY email_address
     HAVING COUNT(o.order_id) > 1;